2b^2+b-3=3

Solution for 2b^2+b-3=3 equation:

Simplifying
2b2 + b + -3 = 3

Reorder the terms:
-3 + b + 2b2 = 3

Solving
-3 + b + 2b2 = 3

Solving for variable 'b'.

Reorder the terms:
-3 + -3 + b + 2b2 = 3 + -3

Combine like terms: -3 + -3 = -6
-6 + b + 2b2 = 3 + -3

Combine like terms: 3 + -3 = 0
-6 + b + 2b2 = 0

Factor a trinomial.
(-2 + -1b)(3 + -2b) = 0

Subproblem 1
Set the factor '(-2 + -1b)' equal to zero and attempt to solve:

Simplifying
-2 + -1b = 0

Solving
-2 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1b = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -1b = 0 + 2
-1b = 0 + 2

Combine like terms: 0 + 2 = 2
-1b = 2

Divide each side by '-1'.
b = -2

Simplifying
b = -2
Subproblem 2
Set the factor '(3 + -2b)' equal to zero and attempt to solve:

Simplifying
3 + -2b = 0

Solving
3 + -2b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -2b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -2b = 0 + -3
-2b = 0 + -3

Combine like terms: 0 + -3 = -3
-2b = -3

Divide each side by '-2'.
b = 1.5

Simplifying
b = 1.5
Solution
b = {-2, 1.5}